ChemE – Solved

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πŸ™ 6) ! -1
βˆ’ 2 + = sin ( )
βˆ’ =
+ 2 =
(1) (5)
(1) = = 1, (5) = βˆ’1, = 0, (1) = 1

πŸ™ 7) 1 5 – ./ ,! ( ) ! * + ( ’ -2
1
= + βˆ’ + exp (βˆ’ )
(3, )
(1, ) = sin(2″ ) = 0 (, 0) = 1

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