CSE310 – Project #1 (Solution)

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Description

In this project you will implement a variable-length encoding and decoding scheme, and run experiments to evaluate the effectiveness of the the scheme, in addition to the efficiency of your algorithms.
Note: This project is to be completed individually. Your implementation must use C/C++ and ultimately your code must run on the Linux machine general.asu.edu.
You must use a version control system as you develop your solution to this project, e.g., GitHub or similar. Your code repository must be private to prevent anyone from plagiarizing your work.
The rest of this project description is organized as follows. §1 gives the requirements for Project #1 including a description of the encoding and decoding schemes to implement in §1.1 and §1.2, respectively. §2 gives the experiments to design to evaluate the effectiveness and efficiency of the encoding and decoding schemes. Finally, §3 describes the submission requirements for the milestone and full project deadlines.
1 Program Requirements for Project #1
1. Write a C/C++ program that implements the encoding scheme described in §1.1 on plain text. The program must be compiled into an executable named encode and it must take one command line parameter. The parameter is one of the keywords insertion or merge. In all cases, you must read input from stdin, allowing redirection from a text file. You must write the encoded plain text to stdout, allowing redirection to a text file. See §1.1 for detailed instructions.
2. Write a C/C++ program that implements the decoding scheme described in §1.2 on input in the format produced by encoding scheme as prescribed in §1.1. The program must be compiled into an executable named decode. In all cases, you must read input from stdin allowing redirection from an encoded text file. You must write the decoded input to stdout, allowing redirection to a text file. The decoded input will be compared to the original input, i.e., the input prior to encoding. See §1.2 for detailed instructions.
3. Design experiments to evaluate your programs as described in §2. A brief report with figures plotting the data you collect, and interpretation of your results is expected.
Sample text input will be provided on Canvas; use them to test the correctness of your programs. Scripts will be used to check the correctness of your program. Therefore, absolutely no changes to these project requirements are permitted.
1.1 The Encoding Algorithm
Given a normal English text file, for each line of the file:
1. Transform the line into a form that is more amenable to compression. The transformation rearranges the characters in the input into many clusters of repeated characters, in a way that it is possible to recover the original input.
2. Output the compressed form of the transformed line.
To transform a line of text, treat the line as a string of length N. First, compute (and store) every cyclic shift of the string, shifting to the left by one character. Then sort the N cyclic shifts in lexicographic order according to the ASCII code. Note the ordering of characters in the ASCII code.
Table 1 shows the transformation step for the example string Mississippi, of length N = 11. Under Original, rows with index 0,…,10 show the cyclic shift of the string to the left by as many characters, e.g., at index 5 is the string shifted cyclically to the left by 5 characters. Under Sorted, all N cyclic shifts of the string are sorted. (The next column is used in decoding, so it is discussed in §1.2.)
Table 1: Transformation Step of the Encoding Algorithm
Index Original Index Sorted next
0 M i s s i s s i p p i 0 M i s s i s s i p p i 4
1 i s s i s s i p p i M 1 i M i s s i s s i p p 0
2 s s i s s i p p i M i 2 i p p i M i s s i s s 6
3 s i s s i p p i M i s 3 i s s i p p i M i s s 9
4 i s s i p p i M i s s 4 i s s i s s i p p i M 10
5 s s i p p i M i s s i 5 p i M i s s i s s i p 1
6 s i p p i M i s s i s 6 p p i M i s s i s s i 5
7 i p p i M i s s i s s 7 s i p p i M i s s i s 2
8 p p i M i s s i s s i 8 s i s s i p p i M i s 3
9 p i M i s s i s s i p 9 s s i p p i M i s s i 7
10 i M i s s i s s i p p 10 s s i s s i p p i M i 8
The compressed output for a string consists of two lines:
1. The index of the row in which the original string appears in the Sorted column.
2. Form a string last consisting of the last character of each Sorted string. In this string, which is some permutation of the original string, characters form clusters of characters of size one or more. To encode last step through the string from left to right processing the clusters: For each cluster, output the cluster size, followed by the character in the cluster.
For the example string, the original string appears at index position zero in the Sorted column. The last character of each Sorted string is a new string last=ipssMpissii. The first two characters are each in a cluster of size one character. This is followed by a cluster of size two of the character s, and so on. Therefore, the encoding of the string ipssMpissii is:
0
1 i 1 p 2 s 1 M 1 p 1 i 2 s 2 i
1.1.1 Input to the Encoding Algorithm
Some examples of input to your encode program:
encode insertion <ex1.txt >enex1.txt encode merge <ex2.txt >enex2.txt
You must implement both the Insertion Sort algorithm and the Merge Sort algorithms. If the keyword is equal to insertion then use Insertion Sort to sort the strings in Original. Likewise, if the keyword is merge then the sorting algorithm used is Merge Sort.
Do not sort the strings directly because it will result in too much data movement. To be efficient, sort pointers to the strings instead.
1.1.2 Output of the Encoding Algorithm
The output of your encoding scheme is text in which each line of the input is compressed as described in §1.1. In principle, if there are k lines in the file, then 2k lines of output are produced.
1.2 The Decoding Algorithm
Now we describe how to decode, i.e., recover the original string. There are three steps in the recovery:
1. Read the integer giving the index of the row in which the original string appears in the Sorted column.
2. Recover the string last.
3. Using the index, last, and knowledge of the next column, recover the original string.
Recall that the encoded output of the string Mississippi is:
0
1 i 1 p 2 s 1 M 1 p 1 i 2 s 2 i
In this case, the index is zero. Recovering the string last=ipssMpissii from the encoded string is straightforward. Using index, last, and knowing the next column in Table 1, makes decoding easy, as given by the following pseudocode (which, of course, should be generalized):
int index = 0; int next[11] = { 4, 0, 6, 9, 10, 1, 5, 2, 3, 7, 8 };
char last[11] = “ipssMpissii”; x = next[index]; for (i = 0; i < 11; i++) putchar( last[x] ); x = next[x];
This results in the output Mississippi, i.e., the original string is successfully recovered.
From the Sorted strings, here is how the next column is computed. For i = 0,…N − 1, next[i] is the index of the row containing the cyclic shift of Sorted[i] to left by one character. For the example in Table 1, Sorted[0] is Mississippi. Shifting this string to left by one character gives ississippiM, and this string can be found at Sorted[4]. Hence next[0] is 4. Sorted[1] is iMississipp. Shifting this string to left by one character gives Mississippi, and this string can be found at Sorted[0]. Hence next[1] is 0. Sorted[2] is ippiMississ. Shifting this string to left by one character gives ppiMississi, and this string can be found at Sorted[6]. Hence next[2] is 6. Continuing in this way for i = 3…10 gives the values in the column next in the table. Indeed, next is a permutation of the indices 0,…,N − 1.
What is amazing is that the information in the encoding is enough to reconstruct next, and therefore the original message! From last, we know all of the characters in the original string, they’re just permuted. We can reconstruct the first column in Sorted by sorting the characters in last; see Table 2.
Table 2: Reconstructing next from the Encoding
Index Sorted next
0 M ? ? ? ? ? ? ? ? ? i 4
1 i ? ? ? ? ? ? ? ? ? p
2 i ? ? ? ? ? ? ? ? ? s
3 i ? ? ? ? ? ? ? ? ? s
4 i ? ? ? ? ? ? ? ? ? M
5 p ? ? ? ? ? ? ? ? ? p 1
6 p ? ? ? ? ? ? ? ? ? i 5
7 s ? ? ? ? ? ? ? ? ? s
8 s ? ? ? ? ? ? ? ? ? s
9 s ? ? ? ? ? ? ? ? ? i
10 s ? ? ? ? ? ? ? ? ? i
As it turns out, there is a rule that resolves the ambiguity. It is:
If row index i and j both start with the same letter and i < j, then next[i] < next[j].
This rule implies that next[5] = 1 and next[6] = 5.
Why is this rule valid? The rows are sorted, so row 5 is lexicographically less than row 6. This means that the nine unknown characters in row 5 must be less than the nine unknown characters in row 6 (since both rows start with the letter p). We also know that between the two rows that end with p, row 1 is less than row 5. But, the nine unknown characters in row 5 and 6 are precisely the first nine characters in rows 1 and 5. Thus, next[5] = 1 and next[6] = 5 or this would contradict the fact that the strings are sorted.
Using the rule allows all remaining ambiguities to be resolved and all entries of next to be computed.
1.2.1 Input to the Decoding Algorithm
If the input to the encoding scheme consists of k lines, then its output has 2k lines. Thus the decoding scheme iterates k times in order to decode the encoded input.
1.2.2 Output of the Decoding Algorithm
The output of the decoding scheme should equal the input to the encoding scheme. Note that some care will be needed to take care of the LF characters so that the lines match.
2 Experimentation
A standard measure of the “goodness” of a compression algorithm’s effectiveness is the compression ratio. This is the ratio 100%, where t is the total number of characters in the input, and c is the number of clusters in the encoding.
For example, the encoding of Mississippi is 1 i 1 p 2 s 1 M 1 p 1 i 2 s 2 i. In this example, the total number of characters is t = 11, the number of clusters is c = 8, and so the compression ratio is or 27%. (Here, we are ignoring the fact we used integers to code the cluster sizes; this can be done more intelligently but this project is already enough work, right? ,)
Design a set of experiments to study:
1. The average compression ratio; in addition to the average, compute the minimum, maximum, and standard deviation of the compression ratio. You might consider using a box and whiskers plot for this metric.
2. The time to encode each input for each type of sort, i.e., for Insertion and for Merge Sort. Plot the run time as a function of input size.
3. The time to decode each encoded input. Plot the run time as a function of input size.
4. The compression ratio as a function of number of lines encoded. The encoding algorithm has been described as encoding one line at a time. If you instead encode 2,3,… lines at a time, does the compression ratio improve? What do you expect to happen?
An unlimited number of submissions are allowed. The last submission will be graded.
Project State (5%): In a folder (directory) named State provide a brief report (.pdf preferred) that addresses the following:
1. Describe any problems encountered in your implementation for this project milestone.
2. Describe any known bugs and/or incomplete implementation in the project milestone.
4. Cite any external books, and/or websites used or referenced. Implementation (25%): In a folder (directory) named Code provide:
1. In one or more files, your well documented C/C++ source code implementing the encoding scheme required for this project milestone.
The milestone is worth 30% of the total project grade.
Project State (5%): Follow the same instructions for Project State as in §3.1.
Experimentation and Report (15%): In a folder (directory) named Report provide a brief report (.pdf preferred) that addresses the following:
1. Describe the experiments you ran, i.e., the characteristics of the input data you used, such the input sizes in lines and characters, among others.
2. Present figures/tables plotting the results of your experimentation as requested in §2. Use the data you collected to interpret your results. Can you draw any general conclusions about the compression ratio, about the impact of the sorting algorithm on the run time of the encoding scheme, about the impact of input size on the decoding scheme, about the impact on the compression ratio as a function of the number of lines encoded?
Correctness (60%): The same instructions for Correctness as in §3.1 apply except that the input will test both the encoding and decoding schemes.
4 Marking Guide
The project milestone is out of 100 marks.
Project State (5%): Summary of project state, use of a zip file, and directory structure required (i.e., a folder/directory named State and Code is provided).
Implementation (25%): 15% for the quality of implementation in your encoding scheme; 5% for reading from stdin and writing to stdout; 5% for a working makefile.
Correctness (70%): For correct output at least 7 tests of sample input.
The full project is out of 100 marks.
Project State (5%): Summary of project state, use of a zip file, and directory structure required (i.e., a folder/directory named State, Report, and Code is provided).
Experimentation and Report (15%): Experiment design, results (plots/tables) of results gathered, and interpretation of results.
Implementation (20%): 15% for the quality of implementation in your code; 5% for reading from stdin and writing to stdout, and for a working makefile.
Correctness (60%): 60% for correct output on at least 10 tests of sample input.
Comments will be provided to you when your graded project is returned.

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