CS453 – Assignment 2 (Solution)

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1. Among all simple graphs (no loops, no parallel edges) with 𝑛 = 100 vertices, determine (with justification) the minimum possible and the maximum possible values for π‘š, the number of edges such a graph could have.

2. Let 𝐺 be the simple graph with vertex set

𝑉 = {00, 01,02, 10,11, 12, 20,21, 22}; |𝑉| = 9

and where vertices π‘Žπ‘ and 𝑐𝑑 are joined by an edge when exactly one of the following conditions holds (so there are no loops):

π‘Ž = 𝑐 or 𝑏 = 𝑑.

A. Sketch 𝐺; you are allowed to do this by hand and then copy your sketch electronically into your PDF submission.
B. Determine π‘š, the number of edges of 𝐺.

3. The β€œgrid graph” π‘ƒπ‘Ÿ,𝑠 is the cartesian product of the two paths π‘ƒπ‘Ÿ and 𝑃𝑠. For instance, 𝑃3,4 is drawn below:

A. In terms of π‘Ÿ and 𝑠, find a formula for the number of vertices of the grid graph π‘ƒπ‘Ÿ,𝑠.
B. In terms of π‘Ÿ and 𝑠, find a formula for the number of edges of the grid graph π‘ƒπ‘Ÿ,𝑠.

4. Recall that a graph 𝐺 is β€œcubic” if and only if it is 3-regular.
A. Show that there exists no cubic graph with an odd number of vertices.
B. For every integer 𝑛 β‰₯ 3, show that there exists a simple cubic graph (no loops, no parallel edges) with 2𝑛 vertices. One way to do this is to produce a construction, i.e., give a set of 2𝑛 vertices and a recipe for when vertices are joined by edges for constructing such graphs.

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